Two parallel metal plates carry charges +Q and – Q respectively. A test charge q 0 placed between them experiences a force F. Now the separation between the plates is doubled, then the force on the test charge will be –
Text Solution
Verified by ExpertsThe correct answer is:
A
Initially, the force on charge
is


The electric field is,

If the separation between the plates is doubled E will remain same as its independent of distance.

Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
An electric dipole when placed in a uniform electric field E will have minimum potential energy, if…
The electric potential at a point on the axis of an electric dipole depends on the distance r of th…
An electric dipole of moment p is placed in the position of stable equilibrium in uniform electric …
An electric dipole consisting of two opposite charges of each separated by a distance of is place…
An electric dipole of moment is placed normal to the lines of force of electric intensity , then …
The distance between the two charges +q and -q of a dipole is r. On the axial line at a distance d …